Does 0=1? (Math proof I randomly found)

It might "go on forever" but there is still an even number of ones.
So:
0=(1-1)+(1-1)+(1-1)+(1-1)
changes to
0=1+(-1+1)+(-1+1)+(-1+1)-1
then you remove the "infinite" (-1+1)s
0=1-1
All the sets in parentheses may be infinite but after you change the parentheses, there will still be the same number of +1s and -1s because it's an infinite number of sets of both of them, leaving a 1 at the front and a -1 at the end.

there is a completely different proof that proofs 2=1
the problem with this one is that you need to substitute for all of the same parts. So you have the same thing on both sides.

Well the math you said there is right. But 0=0 and 1=1 so...?

Haha Cool boy

No, you're right! My math teacher taught us that in class. Something about 0 can't exist In some equations, idk. Strange