allright this is not my ****** home work iam serious i have an exam tommorw and id really appreaciate it if you could help me with this question please click on the link http://www.xtremepapers.me/CIE/Cambridge… the question number is 25 if you cannot solve the question or wish to type in something negative to compensate for your lack of knowledge then leave
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The area under the graph gives distance travelled, hence area uptill 20 seconds:
0.5*base*height=0.5*20*u==>10*u.
hence D=10u
2D=20u.
when the car is at 30 seconds, the area between 20 and 30 seconds:
=base*height==>10*u.
total distance travelled:
=10u+10u
=20u,
Hence the time is 30 seconds until the car travels to 2D.
0.5*base*height=0.5*20*u==>10*u.
hence D=10u
2D=20u.
when the car is at 30 seconds, the area between 20 and 30 seconds:
=base*height==>10*u.
total distance travelled:
=10u+10u
=20u,
Hence the time is 30 seconds until the car travels to 2D.
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Dunno