Math help!!!!?!?!?!!?!?!?!?!?!
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Math help!!!!?!?!?!!?!?!?!?!?!

[From: ] [author: ] [Date: 11-05-27] [Hit: ]
6) and radius 3 has the equation (x - 5)^2 + (y - 6)^2 = 9-1.2.......
1.Find the equation of the circle whose center and radius are given.

center ( -2, -5), radius = 1

and

2.Find the equation of the circle whose center and radius are given.

center ( 5, 6), radius = 3

-
(x + 2)^2 + (y + 5)^2 = 1

(x - 5)^2 + (y - 6)^2 = 9

-
A circle with center at (a, b) and radius r, has an equation
(x - a)^2 + (y - b )^2 = r^2

1. Center (-2, -5) and radius 1 has equation (x + 2)^2 + (y + 5)^2 = 1

2. Center (5, 6) and radius 3 has the equation (x - 5)^2 + (y - 6)^2 = 9

-
1. (x+2)squared + (x+5)squared = 1

2. (x-5)squared + (x-6)squared = 9

-
(x+2)²+(x+5)²=1²
and
(x-5)²+(x-6)²=3²
1
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