Gcse maths help!!.............

Anna invested £2500 for n years in a savings account. she was paid 3% per annum compound interest. at the end of n years, anna has £2813.77 in the savings account. work out the value of n.
how the hell do i do this?
explain clearly please cos i dont have an actual clue :')
and don't make ur explanation confusing :P
the more answers the bettter guys!
thankyouu xxx

The formula for this is: final amount = original amount x (1+percentage/100)^number of years
That looks confusing but basically it translates to this:
2813.77 = 2500 x 1.03^n
The 1.03 comes from the fact that you are adding 3% every year.
To get n, the number of years, you need to rearrange this equation.
2813.77/2500 = 1.125508
1.126 = 1.03^n
1.03^4= 1.126
so n= 4

The number of years is 4.
Hope that helps :)

use this formula to find it:

M = P( 1 + i ) to the power of n.


M is the final amount including the principal = £2813.77

P is the principal amount = £2500

i is the rate of interest per year = 3%

n is the number of years invested.

therefore you have:

£2813.77 = £2500 ( 1 + 3%)^n

all you have to do know is manipulate the formula to find n. (that means change the formula around to get n = something)

For compound interest,
A = P x ( 1 + R/100)^n
where
A = total amount
P = principal
R = interest rate
n = number of times compounded
From ur questions,

2813.77 = 2500 x ( 1 + 3/100 )^x

1.1255088 = 1.03^x
if u notice that 1.1255088 can be divided by 1.03 for 4 times,
1,03^4 = 1.03^x
by comparing index,
x = 4

:)