The real number that exceeds its cube by exactly 2 resides between what two integers

title says all

r=r^3+2

so

r^3-r+2=0

and look for the real root.

Chart it around r=0

r = -2 -1 0 1 2
lhs = -4 2 2 2 8

Real root between r=-2 and r=-1

I would like to apologize to peabody for not receiving "best answer." I only gave it to Tim J because he was first to respond.

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Let x = the real number
x - x^3 = 2
x^3 -x +2 = 0
Let f(x) = x^3 -x + 2
f(2) = 8 -2 +2 = 8
f(1) = 1 -1 + 2 = 2
f(0) = 0 -0 +2 = 2
f(-1) = -1 +1 + 2 = 2
f( -2) = -8 +2 +2 = -4
So x lies between -1 & -2