What are the solutions for cosx=√3-cosx when 0≤x<2π

[From: ] [author: ] [Date: 11-05-31] [Hit: ]

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cos(x) = √3 - cos(x)

2*cos(x) = √3

cos(x) = √3/2

x = pi/6, 11pi/6

do you mean cos(x) =(√3) -cos(x)?
==> 2cos(x) = √3
==> cos(x) = (√3)/2
==> x = π/6 or 2π- π/6

good luck...

I DON'T KNOW I'M A VIRGIN!!!!!!!!!!

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