Question about dividing exponents
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Question about dividing exponents

[From: ] [author: ] [Date: 11-06-06] [Hit: ]
otherwise, put it on the denominator) x- x^2 = x^-1which is negative,......
X^3 -16x^2 +64x
--------------------
x^3-8x^2. I know the answer is x-8 over x but how do they arrive at this?

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(x^3 -16x^2 +64x)/(x^3-8x^2)
= x(x^2-16x+64)/x(x^2-8x)
= (x^2-16x+64)/(x^2-8)
= (x-8)^2/(x-8)*x
= (x-8) /x

-
x ( x^2 -16x +64)
-----------------------------
x^2 ( x-8)

x ( x-8) (x-8)
---------------------
x^2 (x-8)

cancel similar terms of numerator and denominator. (x-8)/ (x-8) for example, because it already denotes 1 ryt?

so x-8 is cancelled we have:

x( x-8)
---------
x^2

dividing monomials with exponents ( just subtract them, from the exponent of numerator to the exponent of denominator; if it results to positive, it's on the numerator, otherwise, put it on the denominator)
x- x^2 = x^-1 which is negative, so put it in the denominator

so the answer we'll have is:
(x-8)
--------
x

-
Divide top and bottom by x
(x^2-16x+64)/[x(x-8)] =
(x-8)^2/[x(x-8)] =
(x-8)/x
1
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