There is a 1/2 chance of getting heads. If the coin is tossed 5 times, thats like 1/2 x 1/2 x 1/2 x 1/2 x 1/2. To find probability, you multiply the denominators (2 x 2 x 2 x 2 x 2= 32.) So the probability is 1/32.......
Alternatively, for this type of problem you can simply logic it out:
I need to get one head or more out of 5 coin tosses. The only way I will not get a SINGLE head is if all the coins land on tails. There are 2^5 (32) possible combinations so 31/32 of them will have a head or more.
If you don't know what a tree diagram is this is what yours should look like, albeit with more branches: http://cnx.org/content/m19234/latest/graphics1.png
Well, there are 2 sides of a coin. There is a 1/2 chance of getting heads. If the coin is tossed 5 times, that's like 1/2 x 1/2 x 1/2 x 1/2 x 1/2.
To find probability, you multiply the denominators (2 x 2 x 2 x 2 x 2= 32.) So the probability is 1/32. To find the percentage, divide 1 by 32 = 0.03125 and that is closest to answer A. about 0.03.
Hope that was helpful (:
D. about 0.97 .
