PLEASE SHOW ME HOW TO GET THE ANSWER, I HAVE TO UNDERSTAND THE FULL WORK!! THX!
-
Note that, since tan(bx) = sin(bx)/cos(bx), we see that vertical asymptotes will occur when division by zero occurs. We see that we are dividing by zero when:
cos(bx) = 0.
From the unit circle, this solves to yield the asymptotes to be:
bx = π/2 ± πk ==> x = (π/2 ± πk)/b,
where k is an integer.
I hope this helps!
cos(bx) = 0.
From the unit circle, this solves to yield the asymptotes to be:
bx = π/2 ± πk ==> x = (π/2 ± πk)/b,
where k is an integer.
I hope this helps!