Can some one check my algebra answers for these two questions

1)Find the domain and range of:
a) g(x)=I2x-3I-3
b) h(x)=3x+2/x-1
c) f(x)=x^4-4
Answer
a) domain=all real numbers
range= all real numbers
b) domain=(negative infinity,1)u(1, positive infinity)
range=(negative infinity,3)u(3,positive infinity)
c) domain=all real numbers
range=(-4,positive infinity)

2) If the endpoints of a diameter of a circle are (4,3)and (-3,5), what is the equation of the circle?

Answer
(5-3)^2+(-3-4)^2
=2^2+(-7)^2
=4+49
=53

radius=53/2
midpoint : (1/2, 4)
equation of the circle=(x-1/2)^2+(y-4)^2=53/4

1)
a. correct
b. if you meant (3x+2)/(x-1), then good job.
c. correct

2)Distance formula for the 2 points is
sqrt( (x2-x1)^2 + (y2-y1)^2 )
sqrt ( (-3-4)^2 + (5-3)^2 )
sqrt ( (-7)^2 + (2)^2 )
sqrt ( 49 + 4 )
sqrt ( 53 ) = diameter = 7.28011

radius = diameter/2 = sqrt ( 53 )/2 = 3.64005
midpoint = correct
equation = correct

Looks like you just didn't type that you had the square-root (sqrt) around the 53. If it was an incident that you didn't type that but it's on your homework then everything is OKAY!

Hope this helps! :)

no. no i can't...i'm sorryyyy