Help with this algebra question? Can you please answer

Find the third, seventh, and tenth terms of each sequence:

1. A(n) = -5 + (n - 1)(2)

2. A(n) = 1.2 + (n - 1)(-4)

3. A(n) = 8 + (n - 1)(-3)

1).
A(n) = -5 + (n - 1)(2)
A(3) = -1
A(7) = 7
A(10) = 13

2).
A(n) = 1.2 + (n - 1)(-4)
A(3) = -6.8
A(7) = -22.8
A(10) = -34.8

3).
A(n) = 8 + (n - 1)(-3)
A(3) = 2
A(7) = -10
A(10) = -19

'n' is the number of the term in the sequence. So if, for example, you wanted to find the seventh term, you would just plug in 7 for n.

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