How do I make an equation with these two points

(-1,-1) (1,-6)

Do you mean find the equation of the line ?
First find slope
y2 - y1 / x2 - x1
- 6 - - 1 / 1 - - 1
-5 / 2
equation of line
y - y1 = m(x - x1) Plug in the coordinates and the slope (m)
y - - 1 = - 5/2(x - - 1)
y + 1 = - 5/2x - 5/2
y = - 5/2x - 5/2 - 1
y = - 5/2x - 7/2

THE ABOVE ANSWER IS RIGHT, YOU MISSED THE MINUS SIGN INFRONT OF THE 5/2X

-6-(-1)/1-(-1)= The slope of the points then you fill in the slope in to the equation y=Mx+b which M stands for slope keep the x next to the slope then pink either (-1,-1) or (1,-6) and fill in the x and y in y=Mx+b. So if the slope is -5/2 and you fill it in the equation y=mx+b.y=-5/2x=b to find be put in the point you chose so say you chose(-1,-1) so put (x,y) in the equation -1=-5/2(-1)+b and solve for b. You should get -7/4.

If its a linear equation use:

Gradient = change in y / change in x = y1-y2 / x1-x2 = -1- -6/-1-1 = -5/2

Therefore y = -5/2 x + c

to find c we need to know what y ix for x=0. Hope this helps.

slope = m = ( - 6 - ( - 1))/(1 - ( - 1))

m = - 5/2

- 5/2 = (y - ( - 1))/(x - ( - 1))

- 5/2 = (y + 1)/(x + 1)

- (5/2)*(x + 1) = y + 1

y = - (5/2)*x - 5/2 - 1

y = - (5/2)*x - 7/2

Find slope.

(y2-y1)/(x2-x1)

(-6+1)/(1+1) =-5/2

y-y1=m(x-x1)

y+1=(-5/2)(x+1)