Chemisty equation problem 3
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Chemisty equation problem 3

[From: ] [author: ] [Date: 11-08-10] [Hit: ]
0 mL = .5.00g HCl (1 mol HCl / 36.45 g HCl) ≈ .M = .137 mol / .......
A solution is made by dissolving 5.00g of HCl in enough distilled water to give a final volume of 500.0 ml. Calculate the Molarity of the solution.

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M = mol / liters
500.0 mL = .5000 L

5.00g HCl (1 mol HCl / 36.45 g HCl) ≈ .137 mole HCl

M = .137 mol / .5000L ≈ 0.274 M

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0.274 M
1
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