A PIE WITH CIRCULAR CROSS SECTIONS IS 24 CM ACROSS THE TOP , 16 CM ACROSS THE BOTTOM, AND 6 CM DEEP. FIND THE VOLUME OF THIS DISH? Solve using integrals
Can some one please help me with this question? I am very much lost =(
Can some one please help me with this question? I am very much lost =(
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Hello
Place the pie with the bottom center at the origin. The line between the rim of the bottom and the rim of the top is
y = 6/4*x - 12
Rotate this line from x = 8 to x = 12 about the y axis, so that you get the volume ABOVE the line.
Use
V = pi∫(x^2(f'(x)dx
V = pi∫(x^2*(6/4)dx from x = 8 to 12
V = pi[6/12*x^2]
V = pi[12^3/2 - 8^3/2]
V = 608pi
Regards
Place the pie with the bottom center at the origin. The line between the rim of the bottom and the rim of the top is
y = 6/4*x - 12
Rotate this line from x = 8 to x = 12 about the y axis, so that you get the volume ABOVE the line.
Use
V = pi∫(x^2(f'(x)dx
V = pi∫(x^2*(6/4)dx from x = 8 to 12
V = pi[6/12*x^2]
V = pi[12^3/2 - 8^3/2]
V = 608pi
Regards