I tried doing this but I didn't understand after I saw that the answer is No solutions, can u please explain this to me:
|2x-8|-2= -1 and i know u have to set up another equation which was |2x-8|+2= 1
what wld u do next in order to get the answer i already mentioned?
also i had some inequality questions...
I noticed that when i have an equation such as |2x-3|<11 and i follow order of operations by dividing both sides by 2 i get the wrong answer, but when i break o of o rules and add 3 i get the right answer...why is that?
|2x-8|-2= -1 and i know u have to set up another equation which was |2x-8|+2= 1
what wld u do next in order to get the answer i already mentioned?
also i had some inequality questions...
I noticed that when i have an equation such as |2x-3|<11 and i follow order of operations by dividing both sides by 2 i get the wrong answer, but when i break o of o rules and add 3 i get the right answer...why is that?
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for |2x-8|+2= 1 there is no sol. cause
u'll get |2x-8| = -1 abs.value cannot be negative, it is always positive, it's distance from the origin, distance is positive. so no sol.
for |2x-8|-2= -1 i get x= 9/2 , 7/2 however if x is element of integers, then no sol.
- 11 < 2x-3 < 11 x> -4 and x<7 -4 < x < 7
u'll get |2x-8| = -1 abs.value cannot be negative, it is always positive, it's distance from the origin, distance is positive. so no sol.
for |2x-8|-2= -1 i get x= 9/2 , 7/2 however if x is element of integers, then no sol.
- 11 < 2x-3 < 11 x> -4 and x<7 -4 < x < 7
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Y1: |2x-8|-2= -1
Y2: |2x-8|+2= 1
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put that in the calculator and compare:
No solution: Parallel lines ( you know what that means )
one solution : intersecting lines ( both lines cross each other )
infinite solutions: consistent ( one line over the other )
all thanks to the calculator, it's the easiest way to figure out these equations.
for the inequality question:
the ' -3 ' becomes positive then you add it to the ' 11 ' becomes 14
so it's |2x| ( the arrow thing ) 14
then you get 2 and divide it by 14 so ' 14\2 '
final answer: ' |x| = 7 ' ...I THINK . lol it's been like 5 months since i learned this. you already started school ? :/
Hope i helped you a little bit, good luck.
Y2: |2x-8|+2= 1
----------------
put that in the calculator and compare:
No solution: Parallel lines ( you know what that means )
one solution : intersecting lines ( both lines cross each other )
infinite solutions: consistent ( one line over the other )
all thanks to the calculator, it's the easiest way to figure out these equations.
for the inequality question:
the ' -3 ' becomes positive then you add it to the ' 11 ' becomes 14
so it's |2x| ( the arrow thing ) 14
then you get 2 and divide it by 14 so ' 14\2 '
final answer: ' |x| = 7 ' ...I THINK . lol it's been like 5 months since i learned this. you already started school ? :/
Hope i helped you a little bit, good luck.
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To get |2x-8|-2= -1, the only way is |2x-8|=1, that is -(2x-8)=1, x=7/2, or 2x-8=1, x=9/2.
If you check, x=7/2, 9/2 both satisfy the equation.
To |2x-8|+2= 1, the only way is |2x-8|=-1, no x that can satisfy. No solution.
The other way is to plug in x=7/2, 9/2 in |2x-8|+2= 1, never satisfy. (remember, must satisfy both)
|2x-3|<11 means -(2x-3)<11 or 2x-3<11, giving x>-4 or x<7.
Try with x=6, a value between 4 and 7, |2x-3|<11, 9<11.
With x=-10, fail; x=8, fail.
Solution is (-4, 7).
If you check, x=7/2, 9/2 both satisfy the equation.
To |2x-8|+2= 1, the only way is |2x-8|=-1, no x that can satisfy. No solution.
The other way is to plug in x=7/2, 9/2 in |2x-8|+2= 1, never satisfy. (remember, must satisfy both)
|2x-3|<11 means -(2x-3)<11 or 2x-3<11, giving x>-4 or x<7.
Try with x=6, a value between 4 and 7, |2x-3|<11, 9<11.
With x=-10, fail; x=8, fail.
Solution is (-4, 7).