Where P is (-2,6), R is (-10,4) and segment RT is a diameter of circle P, find the coordinates of T.
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Where P is (-2,6), R is (-10,4) and segment RT is a diameter of circle P, find the coordinates of T.

[From: ] [author: ] [Date: 11-08-24] [Hit: ]
Distance along Y from P to T is +2.So T = (Xp + 8, Yp + 2) = (-2 + 8, 6 + 2) = (6,......
Thank you so much, just wanted to check my answer, an explanation of your work would be very helpful!

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(6, 8)

RT is the diameter so passes from R, through P, to T. The distance along X from R to P will be equal to the distance along X from P to T. Same thing along Y.

Distance along X axis from R to P is +8.
Distance along Y axis from R to P is +2.

So, distance along X from P to T is +8.
Distance along Y from P to T is +2.

So T = (Xp + 8, Yp + 2) = (-2 + 8, 6 + 2) = (6, 8)
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