How do you find the gradient of the tangent to the curve y= x^2+ 5x+ 6 at the point (1,12)?
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Differentiate the given curve:
so,
dy/dx = 2x + 5
Now since the point (1,12) its x co-ord is 1
So put this in the dy/dx equation and value of slope would be 7
so,
dy/dx = 2x + 5
Now since the point (1,12) its x co-ord is 1
So put this in the dy/dx equation and value of slope would be 7
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Hello
The gradient ( or slope) of the tangent to a curve at a point is the value of the derivative at that point
Derivative : 2x+5
When x=1, the derivative is 2(1) + 5 = 7
Now look at the graph :
http://www.imagup.com/data/1127540530.ht…
Hope it helped
Bye !
The gradient ( or slope) of the tangent to a curve at a point is the value of the derivative at that point
Derivative : 2x+5
When x=1, the derivative is 2(1) + 5 = 7
Now look at the graph :
http://www.imagup.com/data/1127540530.ht…
Hope it helped
Bye !