Please help! Thanks :P
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part one is 64a^6/?do you mean (2a)? = 32a^5 [you seem to, ]
now, when do (32a^5)^k ... k would be 2/5 so that a^( 5 * (2/5) = a^2
BUT 32^(2/5) does not equal 32 ( is = 4 ) ... so I cannot get to (32a^5)^k = 32a^2
the way I came. [ but would get (32a^5)^k = 4a^2 ] ... typo on your part??
if k = 32a^5 then k would = 1, to give the original result (<< unlikely problem answer)
now, when do (32a^5)^k ... k would be 2/5 so that a^( 5 * (2/5) = a^2
BUT 32^(2/5) does not equal 32 ( is = 4 ) ... so I cannot get to (32a^5)^k = 32a^2
the way I came. [ but would get (32a^5)^k = 4a^2 ] ... typo on your part??
if k = 32a^5 then k would = 1, to give the original result (<< unlikely problem answer)
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K= enough
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(2a)