A company dedicated to the manufacture of chemicals had a spill of a chemical contaminant in a local river, has been determined by the department of waste management in conjunction with the department of administration and finance the cost generated by the spill will depending on the time spent active chemical in the water, which is given by the following function in thousands of pesos
c (T) = (2.5T +3500 t ^ 2) / (50t ^ 2 +2)
Determine what the cost to the company as time goes on.
(t) = ∞
when t goes to infinity
c (T) = (2.5T +3500 t ^ 2) / (50t ^ 2 +2)
Determine what the cost to the company as time goes on.
(t) = ∞
when t goes to infinity
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The correct answer has already been mentioned above and its 70 pesos.
You can attempt this problem as a problem on Limits. That is t --> ∞
Divide the numerator and denominator by t^2. Then replace t by ∞.
You will get 70 as answer.
You can attempt this problem as a problem on Limits. That is t --> ∞
Divide the numerator and denominator by t^2. Then replace t by ∞.
You will get 70 as answer.
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3500t^2/50t^2
Only thing you need to look at if the leading t's on both top and bottom are to the same degree is their coefficient.
So we are left with 3500/50 = 70
Only thing you need to look at if the leading t's on both top and bottom are to the same degree is their coefficient.
So we are left with 3500/50 = 70
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horizontal asymptote where 3500/50 = 70