What's the equation of the secant line containing (1, f(1)) and (2, f(2))
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What's the equation of the secant line containing (1, f(1)) and (2, f(2))

[From: ] [author: ] [Date: 11-09-11] [Hit: ]
f(1) = 1 - 3(1) = -2, and f(2) = 1 - 3(2) = -5.The two points are therefore (1, -2) and (2, -5).m = (-5 - (-2))/(2 - 1) = -3/1 = -3.......
f(x) = 1 - 3x

Explain please!

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Use the standard formula for slope: change in y divided the change in x. Get the y-values:

f(1) = 1 - 3(1) = -2, and f(2) = 1 - 3(2) = -5.

The two points are therefore (1, -2) and (2, -5). The slope is

m = (-5 - (-2))/(2 - 1) = -3/1 = -3.
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