Help Limits in Calculus!?!

lim (7x) / cot( 3x)
x->0

lim h (4+2/h^2)
x->0

f(x)= x^2+16
lim x->2 f(x)-f(14) / x-2

lim (2x^2) / 1-cos(6x)
x->0

Thank you sooo much

7x/cot 3x = 7x/(cos 3x/sin 3x) = 7x sin 3x/cos 3x --> 0

4 + 2/h^2 --> ∞

[(x^2 + 16) - (14^2 - 16)](x - 2) = (x^2 - 196)/(x - 2) --> DNE

2x^2/(1 - cos 6x) --> 4x/(6 sin 6x) = 4x/sin 6x • 1/6 = 6x/sin 6x • 1/6 • 2/3 --> 1 • 1/6 • 1/3 = 1/18