Whats the equation for the line tangent to y=-3-6x^2 at (-2,-27)

y'= -12x
y' at -2 = -12(-2)
y' at -2 = 24
so the slope at x = -2 is 24
y-y1=m(x-x1)
y+27=24(x+2)
y=24x+48-27
y=24x+21

rewrite equation so it follow y=mx+b which would be y=-6x^2-3
the slope m=-6
use point slope form to find where the line is tangent at (-2,-27)
so y+27=-6(x+2)
y+27=-6x+12
y=-6x-39

it doesnt matter your never gonna use it in real life