Geometry help!! Check the problem please!!
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Geometry help!! Check the problem please!!

[From: ] [author: ] [Date: 11-09-27] [Hit: ]
If Angle JDR is the same size (has the same measure) as Angle BDJ, then you are correct.If Angle JDR is the same size (has the same measure) as Angle BDJ, then you are correct.......
I have a question that says,

"find the value of each variable"

The problem looks like this:

m(the sign kinda looks like a less than except its more open kinda like an acute angle)BDJ= 7y +2, m(same sign again)JDR= 2y +7

So what I did was this:

7y+2= 2y + 7
5y= 5
y=1

Then I plugged it back into the y in the original problem and got 9 is this correct? If not can you show me the correct way to do it?

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I believe you are correct, because you would do:

7y+2=2y+7 (as you did)
7y-2y and 7 - 2
5y=5

And yeah y would equal 1.

And if you wanna check it you just plug it back in:

7(1)+2=2(1)+7
7+2=2+7
9=9

Good Job!

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Read the sign you're referring to as "angle"

Angle BDJ = 7y+2
Angle JDR = 2y+7

If Angle JDR is the same size (has the same measure) as Angle BDJ, then you are correct.

-
Read the sign you're referring to as "angle"

Angle BDJ = 7y+2
Angle JDR = 2y+7

If Angle JDR is the same size (has the same measure) as Angle BDJ, then you are correct.

-
you are correct
1
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