Suppose that the probability of a success on a trial is 0.05. Find the probability of getting 2
successes in 100 trials.
successes in 100 trials.
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this is a routine binomial distribution q
number of trials n = 100,
probability of success in a single trial = p = 0.05,
probability of failure in a single trial = q = 1-p = 0.95
P[x = 2] = 100c2* 0.05^2 *0.95^98 = 0.08118 <----------
you can get an understanding of the "why" & "how" of the formula from
http://easycalculation.com/statistics/le…
number of trials n = 100,
probability of success in a single trial = p = 0.05,
probability of failure in a single trial = q = 1-p = 0.95
P[x = 2] = 100c2* 0.05^2 *0.95^98 = 0.08118 <----------
you can get an understanding of the "why" & "how" of the formula from
http://easycalculation.com/statistics/le…
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C(100,2)*(.05)²(.95)^98 = .08118