Algebra help; system of 3 equations with 3 variables(fractions)

i don't know how to type this problem out but here goes, its part of a system of three equations:
i just need to know how to remove fractions

[(x+2)/6]-[(y+4)/3]+z/2=0

[(x+1)/2)]+[(y-1)/2]-z/4=9/2

[(x-5)/4]+[(y+1)/3]+[(z-2)/2]=19/4

You need to multiply each term of the equations by the least common multiples of the divisors.

For example, when [(x+2)/6]-[(y+4)/3]+z/2=0 is multiplied by 6 you get
(x+2)-2(y+4)+3z=0

Do the same for the second equation ( using a multiplier of 4) and the third (using 12)