Algebra question(factorising)

p^2-3pq+2q^2
and
r^2-6rp+8p^2

please anwer this for me and also with specific solution (so i could understand easily)
Thanks

factor first and last term of each expression.
Factors of p^2 is p and p. Factors of 2q^2 are 2q and 1q. Look at middle term (-3). What two factors of 2 when added together will result in -3pq and when multiplied together will result in + 2q^2?
Only factors are -1q, & - 2q.
(p - 2q)(p - 1q)

Same for next expression.
Factors of +8 are 8 & 1 or -8 & -1, 4 & 2, or -4 & -2.
Only -4 & -2 work.
(r - 4p)(r - 2p)

p² - 3pq + 2q² = 0
p² - 3/2pq = - 2q² + (- 3/2q)²
p² - 3/2pq = q²([- 8 + 9]/4)
(p - 3/2q)² = 1/4q²
p - 3/2q = ± 1/2q

= p - q([3 + 1]/2), = p - q(4/2), = p - 2q
= p - q([3 - 1]/2), = q - q(2/2), = p - q

Answer: (p - 2q)(p - q)
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r² - 3rp = - 8p² + (- 3p)²
r² - 3rp = - 8p² + 9p²
(r - 3p)² = p²
r - 3p = ± p

= r - 3p - p, = r - 4p
= r - 3p + p, = r - 2p

Answer: (r - 4p)(r - 2p)

COEFF of p^2 = +1

( +1) ( +2) = +2

FIND FACTORS OF +2 which add up to - 3 ( COEFF of pq )

(-1) ( -2) = +2

p^2 - pq -2pq + 2q^2

p ( p - q) -2q ( p - q)

( p - 2q) ( p - q) ANSWER

2) USE SAME METHOD
r^2 -4rp -2rp +8p^2

r ( r - 4p) - 2p( r - 4p)

( r - 2p) ( r - 4p) ANSWER

1) (p-2q)(p-q)
2) (r-4p)(r-2p)

¤ p^2-2pq-pq+2q^2=p(p-2q)-q(p-2q)=(p-2q)(p…
¤ r^2-4rp-2rp+8p^2=r(r-4p)-2p(r-4p)=(r-4p)…

p^2-3pq+2q^2 = (p-2q)(p-q)

r^2-6rp+8p^2 = (r-2p)(r-4p)