Rationalize the denominator

5/√x -3

what is five over square root of x minus 3

?? any ideas? where do i start first? help please

We can multiply by sqrt(x)+3 both side numerator and denominator

so it becomes

5/(sqrt(x)-3) *(sqrt(x)+3)/(sqrt(x)+3)

=5(sqrt(x)+3)/x-9

=(5sqrt(x)+15)/(x-9)

Ans:
5/(sqrt(x)-3)*((sqrt(x)+3)/sqrt(x)+3)
=(5*(sqrt(x)+3))/((sqrt(x)-3)*(sqrt(x)…
=(5*(sqrt(x)+3))/(x-9)

you multiply the top and the bottom of the equation by (sqrt(x-3)), will leave a (x-3) on the bottom

5/√x- 3 =

[5/√x+3 ]/[(√x -3)( √x +3)]

=[5/√x+3 ]/[x-9]