Find the smallest positive value of x, if (x,2) lies on the graph of y=4cos1/2 (x-(pi/3)) + 1

Since y = 2;

2 = 4cos1/2 (x - pi/3) + 1

1 = 4cos1/2 (x - pi/3)

1/4 = cos1/2(x - pi/3)

arc cos 1/4 = 1/2(x - pi/3)

1.3181(rad) = 1/2(x - pi/3)

2.6362(rad) = x - pi/3

x = 2.6362(rad) + pi/3(rad)

x = 3.6434(rad) approx.