Use integration by parts to evaluate the integral.
∫xe^3x*dx
∫xe^3x*dx
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let u = x and dv = e^(3x) dx to get { [1/3]x e^(3x) - [1/9] e^(3x) }
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Doing it by looking.\
This integral is = to e^3x*x/3+e^3x/9+c
The end
This integral is = to e^3x*x/3+e^3x/9+c
The end
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let 3x=t x=t/3 dx=dt/3 I= intt/3*e^t*t/3 int 1/9 t8e^tdt int by parts calculate