Given g(x)= x^2+12x find a g(3) b(g-5) and C(0)
(3)^2+12(3)=
9+36=45
now for b-
(-5)^2+12(-5)
25+(-60)=-35
and I know the next one is zero when I replace all the x's with 0.
So did I do this right? Full points will be awarded!
(3)^2+12(3)=
9+36=45
now for b-
(-5)^2+12(-5)
25+(-60)=-35
and I know the next one is zero when I replace all the x's with 0.
So did I do this right? Full points will be awarded!
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You did this right if you mean:
a) g(3)
b) g(-5)
c) g(0)
If so this all looks correct! :)
a) g(3)
b) g(-5)
c) g(0)
If so this all looks correct! :)
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I think your b part is wrong:
b(g-5) is the same as g(x) -5.
So your new equation should probably just look like this:
b(g-5) = x^2+12x -5
The others look right though (although it's a little weird that 'C'(0) was used...)
b(g-5) is the same as g(x) -5.
So your new equation should probably just look like this:
b(g-5) = x^2+12x -5
The others look right though (although it's a little weird that 'C'(0) was used...)
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Yeah..your answer is right...no doubt