Graphs and curves!!!! Help

how can the rational function
y=2(x+3)+1 / x+3
be written as:
y = 1/x+3 +2 ???

Thanks :)

Just before I start, i'd like to highlight to you that you've forgotten to put the brackets in your 2nd equation - it should be written as: y = 2 + [1/ (x+3) ]

So, if we start with the first equation, you can see that it can be written slightly differently:

y= [ 2(x+3)/(x+3) ] + [1/ (x+3) ]

So, now, if you look at the fraction to the LHS, you'll see that the (x+3) can be cancelled out so the fraction would simplify to just 2:

y = 2 + [1/ (x+3) ]

Hope that helps :)

You can split this into the sum of two expressions, both with x + 3 on bottom:
2(x + 3) / (x + 3) + 1/(x + 3) and in the first, the (x + 3)'s cancel so it's just
2 + 1/(x + 3) then use commutative property.

y = [2(x + 3) + 1]/(x + 3) = (2x + 6 + 1)/(x + 3) = (2x + 6)/(x + 3) + 1/(x + 3) = 2 + 1/(x + 3)

USE PARENTHESES!!