PLEASE help me solve this problem!
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PLEASE help me solve this problem!

[From: ] [author: ] [Date: 11-11-05] [Hit: ]
22 meters.Now subtract that from 20 meter and use the cos(13) = (20-7.22)/d. Think you can figure it out from here.......
Jake is testing his remote controlled boat in a school swimming pool. the pool is 20m wide. He sets the boat on a course with a bearing of 053 degrees (north is directly across the pool) After the boat has traveeled 12m the motor cuts out. The boat continues toward the far side of the pool at a bearing of 347 degrees. What distance does the boat cover during the second part of the journey before it reaches the other side. Show your working.


THANKS!!! Any help at all would be greatly appreciated!!!

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ok. North is directly across the pool from where the boat is launched. You need to draw yourself a picture of what is going on to understand fully. The first leg of the course is 53 degrees east of north as I understand it and the boat goes 12 meters before motor quits. From that point you need to establish a new north parallel to the old north and then measure 347 degrees from that line and connect to the other side. Once you've done that you have a right triangle that has 360-347 = 13 degrees between north and the line the boat is moving. You know the pool is 20 meters wide so figuring out the northerly 1st leg will involve 12 m as the hypotenuse and 37 degrees as the angle so northerly distance on the 1st leg will be x/12 = sin(37) x = 7.22 meters. Now subtract that from 20 meter and use the cos(13) = (20-7.22)/d. Think you can figure it out from here.
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