Please help me solve these Math problems

(8+10i)(5-8i)

3/6+7i


solve the log
log3x=6

9^2x=21

Solve given equation
4e^x -4=2

10+5e^2x=17

(8+10i)(5-8i) = 40 + 50i - 64i - 80i^2 = 120 - 14i (since i^2 = -1)

3/6+7i cannot be simplified anymore.

log_3(x) = 6 => x = 3^6 = 729 (assuming log3x is log base 3 of x, just put both sides to the 3^)

9^2x = 21 => log(9^2x) = log(21) => 2xlog(9) = log(21) => x = log(21)/2log(9) => x = 0.6928