WILL GIVE BEST ANSWER !! Express 5x2 + 20x + 6 in the form a(x + b)2 + c.

Express 5x2 + 20x + 6 in the form a(x + b)2 + c. [

Right first divide everything by 5 to make things easier.
So 5x2 +20x +6 / 5 =
x2 + 4x +6/5
Then complete the square
(x + 2)2 -4 +6/5
This makes
(x+2)2 - 14/5
Now because it wants it in the form a(x+b)2 + c, times everything by 5
So..
5(x +2)2 -70/5 =
5(x+2)2 -14
Hope that helped!

5x^2 + 20x + 6
= 5(x^2+4x+6/5)
Then complete the square
a^2+2ab+b^2
such that in this case
a = x, so 2(a)(b) =4x, so b = 2

= 5(x^2+2(x)(2) + (2)^2 +6/5 - 2^2) (
= 5(x^2+4x+4) -5[6/5 -4]
= 5(x+2)^2 - 5(14/5)
= 5(x+2)^2 - 14

5x² + 20x + 6 =
5(x² + 4x + ...) + 6 = ∙ ∙ ∙ ∙ ∙ ∙ ∙ ∙ need to add (4/2)² inside (), subtract 5( added 4) outside
5(x² + 4x + 4) + 6 – 20 =
5(x + 2)² – 14

5x^2 + 20x + 6

= 5(x^2 + 4x + 6/5)

= 5[(x+2)^2 - 2^2 + 6/5)]

= 5(x+2)^2 + 5(- 4 + 6/5)

= 5(x+2)^2 - 14

5x^2 +20x +6
=5(x^2 +4x) +6
=5(x^2 +4x +4 -4) +6
=5(x^2 +4x +4) +5(-4) +6
=5(x+2)^2 -20 +6
=5(x+2)^2 -14

5(x + 2)^2 - 14

5 (2 + x)^2 - 14

x= 5

really...............? no.
do your own work :D
jk,

it's = 5(x+20)^2+6.

a= 5
b= 20
c=6