a valid probability density function: f(x) = kx^2 for 1 < x < 3. If you know the answer please round it to 4 decimals. Thank you.
This is what I did, I took the integral from 1 to 3 then solved for k and I got 0.115 but the answer is wrong!
This is what I did, I took the integral from 1 to 3 then solved for k and I got 0.115 but the answer is wrong!
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Shosho -
Integral from x = 1 to x = 3: kx^2 dx = k(x^3)/3 = k[ (27/3) - (1/3) ] = k(26/3) = 1
k = 3/26 = 0.1154
Hope that helps
Integral from x = 1 to x = 3: kx^2 dx = k(x^3)/3 = k[ (27/3) - (1/3) ] = k(26/3) = 1
k = 3/26 = 0.1154
Hope that helps