Inverse Laplace Transform (s^2 + 2)/(s +1)
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Inverse Laplace Transform (s^2 + 2)/(s +1)

[From: ] [author: ] [Date: 12-02-11] [Hit: ]
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How is this done when the degree of the numerator is larger than the degree of the denominator?

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Use long division first:
(s^2 + 2)/(s + 1) = (s - 1) + 3/(s + 1).

Note: Are there Laplace Transforms for positive powers of s?
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keywords: Transform,Laplace,Inverse,Inverse Laplace Transform (s^2 + 2)/(s +1)
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