Interior Angles of a Polygon help
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Interior Angles of a Polygon help

[From: ] [author: ] [Date: 12-02-17] [Hit: ]
x+35,6.Do the rest yourself, just follow the patterns I showed you in the 2 I did above.......
Solve for x.
1. 5 sides, x+35, x+4, x-18, 2x+1 x+46.
2. 8 sides. 2x-17
3. 9 sides x+7, x-5, x+11, x+29, x+23, x-36, x-20, x+18, x+10.
4. 7 sides 2x+38
5. 6 sides x+81, x+21, 3x+23, 5x+60, x+35, 4x-10
6. 10 sides 5x+61

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Sum interior angles in a polygon is : S= (n-2)*180

1) S= (5 - 2)* 180 = 3* 180 = 540
Add the angles together
6x + 68 = 540
6x = 472
x =78 2/3°

2)S=(8 - 2) * 180 = 1080
8(2x-17)= 1080
2x -17 = 135
2x = 118
x =59

Do the rest yourself, just follow the patterns I showed you in the 2 I did above.
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