Solve the indefinite integral sin(1.5piX+.25pi)

Let u = 1.5piX+.25pi
du = 1.5pi dx
dx = (1/1.5pi) = 2/3pi

∫ sin(1.5piX+.25pi) dx = (2/3pi) ∫ sin(u) du = (-2/3pi) cos(u) + C

=(-2/3pi) cos(1.5piX+.25pi) +C

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dy/dx = sin(1.5pix+0.25pi) y = - cos (1.5pix +0.25pi)/1.5pi +c

No.