Please simplify this equation x2+7x+40

please simplify this and show all steps

the way you simplify the equation x² + 7x + 40 is like this. the formula to solve equations of the format a² + b + c is ((-b ± √(b²-4ac))/2a . our "a" value is 1, our "b" value is 7, and our "c" value is 40. plug those values in and you get (-7 ± √7² - 4(1)(40))/(2*1) and from there you get (-7 ± √-111)/2 . since you cant have a negative value squared you can take out the negative using an imaginary number which we refer to as "i" and the equation looks like this: (-7 ± i√111)/2 . we arent able to do any simplifying after so all we can do is give our solution set which is: x: (-7 + i√111)/2, and x: (-7 - i√111)/2.

Since 2 and 7 both have x, it becomes
x(2+7)+40
2+7=9, so its
x(9)+40
So its x times 9, then add 40.
I THINK.

Hmm is it supposed to be 2x+7x+40? If so...

Collect like terms.. So everything that is an x gets added together (if there were minus signs, you would subtract). So you now have 9x+40 and that's it.

x2+7x+40
discriminant = -111
x1=(-7-isqrt111)/2
x2=(-7+isqrt111)/2

x^2+7x+40=
(x+(7+isqrt111)/2)(x+(7-isqrt111)/2)

there is no equal sign so it is not an equation