I don't know how to solve this can some one figure this out

[From: ] [author: ] [Date: 12-04-05] [Hit: ]

/ (3! x 2!) = 10.So, the probability of exactly 3 projects on schedule and 2 not on schedule is 432 / 16807 * 10 = 4320 / 16807.Finally add up the probability of 5 projects on schedule,......

Now, we're dealing with combinations, and I'm going to give you that answer:
5! / (3! x 2!) = 10.

So, the probability of exactly 3 projects on schedule and 2 not on schedule is 432 / 16807 * 10 = 4320 / 16807.

Finally add up the probability of 5 projects on schedule, plus the probability of 4 on schedule, plus the probability of 3 on schedule:

243 / 16807 + 1620 / 16807 + 4320 / 16807 = 6183 / 16807

6183 / 16807 = approximately 0.368, or 36.8 percent.

I really hope I'm not doing your homework for you. You spent a lot of time asking this and studying my answer, and I spent time answering it. A better use of our time would be for you to study your textbook.

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at least 3 = exact 3 + exact4 + exact 5 = 1 - ( exact0 + exact1+exact2)

p(x=2 ) = (5C2) * (3/7)^2 * (4/7)^3
p(x=1 ) = (5C1) * (3/7)^1 * (4/7)^4
p(x=0 ) = (4/7)^5

add them and subtract from 1

of find ...

12

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