How do I find the perimeter of a triangle given three points

I am trying to find the perimeter of a triangle,
and I am given these points:

A (3, 5)
B (-2, 10)
C (1, -1)

find the distances of its point using distance formula then add

d = √[(x-x1)²+√(y - y1)²]

A( 3, 5), B (-2, 10) , C (1,-1)

Perimeter = distance AB + distance AC + distance BC
distance AB = √[(x-x1)²+ (y-y1)²]
..................= √[(3+2)²+(5-10)²]
..................= √[25+25]
..................= √50
.................. = 5√2

distance AC = √[(3-1)²+(5+1)²]
..................= √[(4+36]
..................= √40
................. = 2√10

distance BC = √[(-2-1)²+(10+1)²]
.................. = √[9+121]
................... = √130

Perimeter = 5√2 + 2√10 + √130
Perimeter = 7.07 + 6.32 + 11.40
Perimeter = 24.79
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JUST distance formula then ADD..hope it hepls

you may not be able to just plot these and measure the lines.
if that doesnt work use the distance formula; d=the square root of ((x2-x1)^2+(y2-y1)^2)
do this for all three distances and then add them together

Good luckkk

Use the distance formula between each point.

http://www.purplemath.com/modules/distfo…

For help on the distance formula.

graph the points.
connect the points with lines.
find the lengths of each od the sides.
add them to find the perimeter.

1. Plot the points
2. Connect them into a triangle
3. Count how long each side is
4. Add the three sides together