An antacid is labeled as having 200 mg of calcium carbonate and 50 mg of magnesium hydroxide in each tablet. How many mL of .091 M HCl will the tablet neutralize?
I'm clueless on how to do this though I feel as if the solution is pretty simple...
Walk me through it please(:
I'm clueless on how to do this though I feel as if the solution is pretty simple...
Walk me through it please(:
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Deal with each ingredient separately:
CaCO3 + 2 HCl → CaCl2 + CO2 + H2O
(0.200 g CaCO3) / (100.0875 g CaCO3/mol) x (2/1) / (0.091 mol/L) = 0.0439 L =
43.9 mL HCl
Mg(OH)2 + 2 HCl → MgCl2 + 2 H2O
(0.050 g Mg(OH)2) / (58.31981 g Mg(OH)2/mol) x (2/1) / (0.091 mol/L) = 0.0188 L = 18.8 mL HCl
Then add the two volumes of HCl:
(43.9 mL HCl) + (18.8 mL HCl) = 62.7 mL HCl
CaCO3 + 2 HCl → CaCl2 + CO2 + H2O
(0.200 g CaCO3) / (100.0875 g CaCO3/mol) x (2/1) / (0.091 mol/L) = 0.0439 L =
43.9 mL HCl
Mg(OH)2 + 2 HCl → MgCl2 + 2 H2O
(0.050 g Mg(OH)2) / (58.31981 g Mg(OH)2/mol) x (2/1) / (0.091 mol/L) = 0.0188 L = 18.8 mL HCl
Then add the two volumes of HCl:
(43.9 mL HCl) + (18.8 mL HCl) = 62.7 mL HCl