Express in terms of base 10 logs

Express each quantity in terms of base 10 logs.

(1) ln(10)


(2) logsub5 (10)


(3) logsub2 (b)

(1) ln(10) = log (10)/log e = 1/log e
(2) logsub5 (10) = log 10/log 5 = 1/log 5
(3) logsub2 (b) = log b/log 2

where log = log base 10

Exactly what "hsueh010" said.

Did you notice: log(a)b = 1/log(b)a?
And also log(a)x = log(10)x/log(10)a, or, more generally, log(a)x = log(b)x/log(b)a....