Find x-intetcept of Equations

Find x-intercepts of equations.

(1) y = 3^(x - 1) - 2


(2) y = 2^(x/2) - 5

x intercept means y=0.

so,

3^(x-) = 2

log 3^(x-1) = log 2

(x-1) log 3 = log 2

x log 3 - log 3 = Log 2

x log 3/ log 3= log 2

x log 3 = LOG 6

X = LOG 6/ LOG 3

= 1.6309

========================

2. y = 2^(x/2) -5

FOR x intercept, y=0

so
2^(x/2) = 5

log 2^(x/2) = log 5

x/2 log 2 = log 5

x/2 = log 5/ log 2

= 2.32

so

x = 2*2.32

= 4.64

y = 3^(x - 1) - 2
0 = 3^(x - 1) - 2
2 = 3^(x - 1)
log(2) = (x-1) log(3)

log(2)/log(3) -1 = x
x = 1.630929754

~~~~~~~~~~~~~~~
y = 2^(x/2) - 5
0 = 2^(x/2) - 5
5 = 2^(x/2)
log(5) = x/2 log(2)
2(log(5)/log(2)) = x

x = 4.64385619

x intercept is when y = 0
1) ln6/ln3
2) 2ln5 / ln2

i doubt you type the equations correctly