in 1997 at Noyes hospital in Dansville, NY reported a string 12- straight girls born in a row
A) If the birth rate of 50% boys - 50% girls is normal, what is the probability of such an event?
B) Of the total birth rate in the hospital in 1997, 80 of 168 total births were girls. What is the probability of this event?
A) If the birth rate of 50% boys - 50% girls is normal, what is the probability of such an event?
B) Of the total birth rate in the hospital in 1997, 80 of 168 total births were girls. What is the probability of this event?
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P(girl for 12 births) = (0.5)^12 = 0.000244
P(80 girls) = (168 nCr 80)(0.5)^80 (0.5)^88 = 0.0509
P(80 girls) = (168 nCr 80)(0.5)^80 (0.5)^88 = 0.0509
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Hey you:
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http://vn.answers.yahoo.com/question/ind…
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This is so easy, its almost an insult to help you... the answer to both is 12%