......
(y^4)+ (x^3) = (y^2) + 11x; (0, 1)
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4y^3 y' + 3x^2 = 2yy' + 11 ---> y ' = 11/2 at (0,1)
keywords: of,find,line,implicitly,tangent,given,point,to,Differentiate,slope,at,the,Differentiate implicitly to find the slope of the tangent line at the given point.
