Solve the given equation in the interval (0,2pi)

[From: ] [author: ] [Date: 12-04-29] [Hit: ]

1) sin(t)= -sqrt(2)/2

2) cos(t)= sqrt(3)/2

3) cos(t)= -sqrt(2)/2

1) 5pi/4, 7pi/4
2) pi/6, 11pi/6
3) 3pi/4, 5pi/4

This is just the unit circle
1)225 and 315
2)30 and 330
3)135 and 225

keywords: equation,the,given,interval,in,Solve,pi,Solve the given equation in the interval (0,2pi)