Simpson's Rule help please.. really quick question

I've done part a) but need help with part b) please

a) Use Simpson's Rule with five ordinates to find an approx value for the integral between 2 and 1 of
ln(3+2x²) dx.

The answer is 1.6607

how do I now do part b)
Use your answer to part (a) to deduce and approx value for the integral between 2 and 1 of
ln(1/3+2x²) dx.

Thanks a lot in advance

I assume by ln(1/3+2x²) you mean (ln(1/(3+2x²))

Think log laws,

ln(1 / (3+2x^2)) can be written as ln( (3+2x^2) ^-1 )

ln(a^b) = bln(a)

so it equals - ln(3+2x^2)

Which would equal -1.6607

(Using maple I got the answer to be 2.0109 and -2.0109)