Calculus Question limits
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Calculus Question limits

[From: ] [author: ] [Date: 12-05-13] [Hit: ]
and the bottom approaches 0. Therefore, the limit will be infinity.-The limit stretches to infinity. Theres no way to rework this such that itll have a solid value. The 1/x forces our hand here.......
i cant seem to get this... Evaluate (1/x) - (1/x²+1) when lim x---> 0

Thank you!

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If you get a common denominator and combine the fractions you'll end up with:

(x² + 1 - x) / (x^3 + x)

As x approaches 0, the top approaches 1, and the bottom approaches 0. Therefore, the limit will be infinity.

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The limit stretches to infinity. There's no way to rework this such that it'll have a solid value. The 1/x forces our hand here.
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