Let a_1 (a sub 1) = 125. For every integer n such that n is greater than or equal to 1, a_n+1 (a sub n+1) = a_n + the square of the sum of the digits of a_n. Find the value of a_6
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You just do this by steps -- 5 of them.
a_2 = 125 + (1+2+5)^2 = 125 + 64 = 189
etc.
a_6 will be pretty big.
a_2 = 125 + (1+2+5)^2 = 125 + 64 = 189
etc.
a_6 will be pretty big.